1900 United States presidential election in Maryland

The 1900 United States presidential election in Maryland took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Maryland voters chose eight electors to the Electoral College, which selected the president and vice president.

Maryland was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York.

United States presidential election in Maryland, 1900

November 6, 1900
  William McKinley by Courtney Art Studio, 1896 WilliamJBryan1902
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai Stevenson I
Electoral vote 8 0
Popular vote 136,185 122,238
Percentage 51.50% 46.23%

President before election

William McKinley

Elected President

William McKinley


United States presidential election in Maryland, 1900[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 136,185 51.50% 8
Democratic William Jennings Bryan 122,238 46.23% 0
Prohibition John Woolley 4,574 1.73% 0
Social Democratic Eugene Debs 904 0.34% 0
Socialist Labor Joseph Maloney 388 0.15% 0
Union Reform Seth H. Ellis 145 0.05% 0
Totals 264,434 100.00% 8
Voter turnout


  1. ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Maryland
Other 1900

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